pic of dimensions 15 m into 12 m into 30 M is dug and the earth taken out is disposed of in a carrier which can carry a maximum load of 5 14 cube of a the least number of rounds the career has to make to dispose of the Earth is
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Given, Dimension of the field = 15 m × 12 m
Dimension of the pit = 8 m × 2.5m × 2m
Volume of earth removed from the pit = 8m × 2.5 m × 2 m = 40 m3
Area of the remaining field
= Area of the field – Area of the pit
= 15 m × 12 m – 8 m × 2.5 m
= 160 m2
Since, the earth removed is evenly spread over the remaining area of the field.
∴ Increase in level of remaining field × Area of remaining field = Volume of earth removed from the pit
Increase in level of remaining field = 40/160 =0.25m
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