Question

Pick a two digit number with distinct digits. Now, reverse
the digits. Subtract the smaller number from the larger
number. The result will always be the multiple of​

Answer 1

Answer:

the result always be the multiple of 1 how it helps

Answer 2

Answer:

hence diff is always divisible by 9

Step-by-step explanation:

let the digit at 10's =x

at 1's=y

let x >y

so No N1 =10x+y

Onreversing the digits

No  N2 =10y+x

N1-N2=10x+y-(10y+x)

=10x-x+y-10y

=9x-9y

=9(x-y)

So the Difference=9* ( big digit-small digit)

hence diff is always divisible by 9

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Ex

63-36=27,=9*(6-3)=27

53-35=18 =9*(5-3)

51-15=36 =(5-1)*9

21-12=9=(2-1)*9