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Given :-
- Parallel sides of Trapezium are = 10cm & 5cm.
- Area of Trapezium = 45cm.²
To Find :-
- Height of Trapezium.?
Formula used :-
- Area of Trapezium = (1/2) * ( sum of Parallel sides) * Height .
Solution :-
Putting Values We get :-
→ 45 = (1/2) * ( 10 + 5) * Height
→ 15 * Height = 45 * 2
→ Height = 3 * 2
→ Height = 6cm. (Option D) (Ans.)
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Properties of Trapezium :-
Some of the important properties of a trapezium are as follows:
- In trapezium, exactly one pair of opposite sides are parallel.
- The diagonals intersect each other.
- The non-parallel sides in the trapezium are unequal except in isosceles trapezium.
- The line that joins the mid-points of the non-parallel sides is always parallel to the bases or parallel sides which is equal to half the sum of the parallel sides.
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_______________________________
- A trapezium whose area is 45cm²
- Two lines of a trapezium whose lengths are 10 cm & 5 cm
_______________________________
- The height of the trapezium.
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As we know that,
➩Area of trapezium = 1/2 × sum of the parallel lines × Height
➩45 = 1/2×(10+5)×Height
➩15×Height = 45 × 2
➩Height = 45×2/15
➩Height = 3×2
➩Height = 6 cm
Therefore,The height of the trapezium is 6 centimetres
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