Question

Pick out nouns from the following passage and separate them into their kinds :
The darkness and the silent procession of the We're Here toward home had built up a
tension in Harvey unlike any he had ever known. He felt the land close around him once
more, with all of its thousands of people asleep. He smelled the earth after rain, and heard
the familiar noise of a switching engine coughing in a freight yard. All these things made
his heart beat fast and his throat dry up. Sitting down by the wheel, Harvey Cheyne
sobbed as though his heart would break.
Nouns
Kinds of noun
​

Answer 1

compound sentence

Explanation:

were playing in the garden when the guests arrived

Answer 2

Answer:

{\underline{\underline{\maltese\textbf{\textsf{\red{Question}}}}}}✠Question

: \implies{\sf\bigg({\dfrac{x}{2} - 6}\bigg) = \bigg({8 - \dfrac{2x}{3}} \bigg)}:⟹(2x−6)=(8−32x)

\begin{gathered}\end{gathered}

{\underline{\underline{\maltese\textbf{\textsf{\red{Solution}}}}}}✠Solution

: \implies{\sf\bigg({\dfrac{x}{2} - 6}\bigg) = \bf\bigg({8 - \dfrac{2x}{3}} \bigg)}:⟹(2x−6)=(8−32x)

{: \implies{\sf\bigg({\dfrac{x - (6 \times 2)}{2}}\bigg) = \bf\bigg({\dfrac{(8 \times 3) - 2x}{3}} \bigg)}}:⟹(2x−(6×2))=(3(8×3)−2x)

{: \implies{\sf\bigg({\dfrac{x - 12}{2}}\bigg) = \bf\bigg({\dfrac{24 - 2x}{3}} \bigg)}}:⟹(2x−12)=(324−2x)

By cross multiplication

: \implies\sf{3(x - 12) = \bf{2(24 - 2x)}}:⟹3(x−12)=2(24−2x)

: \implies\sf{3x - 36 = \bf{48 - 4x}}:⟹3x−36=48−4x

: \implies\sf{4x - 3x = \bf{48 -36}}:⟹4x−3x=48−36

: \implies\sf{x = \bf{12}}:⟹x=12

{\dag{\underline{\boxed{\sf{x =12}}}}}†x=12

Hence, The value of x is 12.

\begin{gathered}\end{gathered}

{{\underline{\underline{\maltese\textbf{\textsf{\red{Verification}}}}}}}✠Verification

: \implies{\sf\bigg({\dfrac{x}{2} - 6}\bigg) = \bf\bigg({8 - \dfrac{2x}{3}} \bigg)}:⟹(2x−6)=(8−32x)

Substituting the value of x

: \implies{\sf\bigg({\dfrac{12}{2} - 6}\bigg) = \bf\bigg({8 - \dfrac{2 \times 12}{3}} \bigg)}:⟹(212−6)=(8−32×12)

: \implies{\sf\bigg({\dfrac{12}{2} - 6}\bigg) = \bf\bigg({8 - \dfrac{24}{3}} \bigg)}:⟹(212−6)=(8−324)

{: \implies{\sf\bigg({\dfrac{12 - (6 \times 2)}{2}}\bigg) = \bf\bigg({\dfrac{(8 \times 3) - 24}{3}} \bigg)}}:⟹(212−(6×2))=(3(8×3)−24)

{: \implies{\sf\bigg({\dfrac{12 -12}{2}}\bigg) = \bf\bigg({\dfrac{24 - 24}{3}} \bigg)}}:⟹(212−12)=(324−24)

{: \implies{\sf\bigg({\dfrac{0}{2}}\bigg) = \bf\bigg({\dfrac{0}{3}} \bigg)}}:⟹(20)=(30)

: \implies\sf{0} = \bf{0}:⟹0=0

\dag{\underline{\boxed{\sf{LHS=RHS}}}}†LHS=RHS

Hence Verified!!