Science, asked by rama3144, 1 year ago

pick the odd one out off the following?? 1.nh4oh 2.znoh 3.cu(oh)2 4.naoh

Answers

Answered by mihirthemega

Hello, Rama!

According to me,

2. ZnOH is the odd one out.

This can be explained as follows:

All hydroxides are proper compounds and follow the octet theory of electrons. But, ZnOH does not do so, and hence the compound cannot be formed.

The valency of Zn is +2, and the valency of OH is -1

So, if we combine both-

Zn(+2) OH (-1)

↓

$ZnOH_{2}$

rama3144: railway board ne naoh answer diya h aur mai nh4oh lagaya ho

rama3144: so in dono me current answes

mihirthemega: well Rama, the first thing that struck to my mind was that ZnOH is not even correct . so... you have to wait

rama3144: aisa bhi to ho sakta h ye ki tin metal oxide or ek NH4oh non metal oxide h

mihirthemega: yes, that is also correct... but why did railway board provided sodium hydroxide??

rama3144: railway board ka answer naoh h to mai objection me dalu ya nai

mihirthemega: han, de do

rama3144: okk bro thanks

mihirthemega: thumbs up

Answered by mindfulmaisel

Answer:

The odd one is $\bold{\mathrm{NH}_{4} \mathrm{OH}}$ .

Explanation:

Here all the given compounds are bases as they have OH- ions which can be easily given. It makes them bases. Usually the hydroxides of metals are basic in nature as they can easily release hydroxyl ions.

In the given options, Cu, Zn and Na are metals and their hydroxides are given whereas $\bold{\mathrm{NH}_{4} \mathrm{OH}}$ is hydroxide which is not a hydroxide of metal but it is a hydroxide of ammonium ion that is composed of N; a non-metal.

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