Physics, asked by ankusharma12, 5 months ago

Picture shows the difference between the real depth and apparent depth of the object under

water. We see the objects closer than their real depth to the surface. We see objects only if the

rays coming from them reaches our eyes. In this picture, ray coming from the fish reaches the

observer‟s eye after refraction. Thus, observer sees the image of the fish at the distance Da

from the surface which is the apparent depth of the fish. On the contrary fish sees the objects

away from their real distances. These are all results of the refraction of light. Following

diagram helps us to calculate this apparent depth of the object under different mediums.Da= Apparant Depth ,Dr= Real Depth , refractive index, n =Dr/Da

An object is at the bottom of a beaker filled with a liquid up to a height of 10 cm(Actual

position of fish). If the refractive index of water w.r.t. air (a

nw ) is 4/3.

(i) Find the apparent depth of the object.

(ii) What is the distance between real object and the virtual object?

(iii) Calculate the apparent depth if water is replaced with a liquid of refractive index 3/2?​

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Answered by veerupathak711
0

Answer:

bhai sorry but thanks for give point

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