Question

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PLEASE ANSWER ​

Answer 1

Answer: Given:

Mass of the hockey ball, m = 200 g = 0.2 kg

Hockey ball travels with velocity, v1 = 10 m/s

To be found:

The change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Solution:

Initial momentum of the ball = mu = 200g × 10 ms-1 = 2000 g.m.s-1

Final momentum of the ball = mv = 200g × –5 ms-1 = –1000 g.m.s-1

Therefore, the change in momentum (mv – mu) = –1000 g.m.s-1 – 2000 g.m.s-1 = –3000 g.m.s-1

This implies that the momentum of the ball reduces by 1000 g.m.s-1 after being struck by the hockey stick.

Explanation: Mark as brainliest

Answer 2

Explanation:

Mass of ball(m)=200g=0.2kg

Initial velocity of ball(u)=10ms

−1

Final velocity of ball(v)=5ms

−1

Therefore, change in momentum (△p) = Final momentum - initial momentum =m(v−u)=0.2×(−5−10)=−3 kgms

−1

=−3 Ns