Piece of resistance wire has resistance of 4.
It is doubled on itself. Now its resistance will
be :
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A resistance wire of 4 ohm resistance is doubled on itself calculate the new resistance of the wire
A resistance wire of 4 ohm resistance is doubled on itself calculate the new resistance of the wireWe consider wire is doubled on it means to fold the length of wire. It means its length will get half and area of cross section will get doubled. Thus, R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω.
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We consider wire is doubled on it means to fold the length of wire. It means its length will get half and area of cross section will get doubled. Thus, R' = p' l'/A' = p (l /2) ÷ 2A = !/4 (p l / A) = 1/4R = 1/4 × 4 = 1Ω
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