pile a can fill a tank in 12 hours and pipe b can empty the tank I. 18 hours both pipes are opened at 6am after some time pipe b is closed and tank is full at 8pm at what time pipe b closed
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pipe A takes 12 hour to fill the tank hence it fills 1/12th of tank in an hour and pipe B empties in 18 hours hence in an hour in 1 hour it empties 1/18th of tank let B is opened for t hours and the total system takes 14 hours to fill the tank so solving the equation (1/12-1/18)*t+(14-t)*1/12=1 it gives t=3 therefore pipe B is closed at 9 am
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