Question

pind the distance of a point p(x,y) from the origin ​

Answer 1

Answer:

Let O be the origin and Q be the foot of the perpendicular dropped from P onto the x axis. 

So ΔOPQ is right-angled at Q.

By definition of coordinates:

OQ=x coordinate of P= distance of P from y axis =∣x∣

Similarly, QP=∣y∣.

Thus, by using Pythagoras theorem on ΔOPQ, we get OP=OQ2+QP2=x2+y2 

Thus the distance of the point P(x,y) from the origin O(0,0) is x2+y2

Step-by-step explanation:

hope this helps mark me as brilliant

Answer 2

Step-by-step explanation:

(x,y) (0,0)

x1=x y1= y x2= 0 y2= 0

formula is

√(x1-x2)square + (y1-y2) square

√ (x-0)square + (y-0)square

√ (x) square +(y) square

Hope it will help u....