Question

Pind the square of (3m +
1/5​

Answer 1

Answer:

answer for the given problem is given

Answer 2

(3m+1/5)^2 = (3m) ^2 + (1/5)^2+(2*3m*1/5)

=9m^2 + 1/25 + 6m/5

=(225m^2 + 1 + 30m)/25 = 0

=225m.^2+30m+1 = 0*25

=225m^2 + 15m + 15m +1

=15m(15m+1) +1 (15m+1)

=(15m+1)(15m+1) = 0

=(15m+1)^2 = 0

√(15m+1)^2 = √0

= 15m + 1 = 0

=15m = -1

=m = -1/15

= 3m+1/5= -3/15+1/5

=-3+3/15

=0/15

=(3m+1/5)^2 =(0/15)^2

=0