Question

Pineapple is 11/2kg and the pear is 5/4 kg.
(a) Find the total weight of these fruits.
(b) How much heavier is the pineapple than the pear.

Answer 1

Answer:

(a) 27/4 kg

(b) 17/4 kg

Step-by-step explanation:

(a)

To find the total weight we will add their Individual weights

11/2 + 5/4

= (11×2)/(2×2) + 5/4

= 22/4 + 5/4

= 27/4 kg

(b)

To find out how much heavier the pineapple is we will subtract their weights

11/2 - 5/4

= (11×2)/(2×2) - 5/4

= 22/4 - 5/4

= 17/4 kg

Hope this helps you.

Answer 2

➣ AnSwer :-

(a) Find the total weight of these fruits.

$\longrightarrow \sf \: \frac{11}{2} + \frac{5}{4}$

LCM of 2 and 4 is 4.

$\longrightarrow \sf \: \frac{11 \times 2}{2 \times 2} + \frac{5}{4}$

$\longrightarrow \sf \: \frac{22}{4} + \frac{5}{4} = \frac{22 + 5}{4}$

$\longrightarrow \sf \: \frac{27}{4}$

Therefore,the total weight of the fruits is $\sf\frac{27}{4} kg$.

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(b) How much heavier is the pineapple than the pear.

$\longrightarrow \sf \: \frac{11}{2} - \frac{5} {4}$

LCM of 2 and 4 is 4.

$\longrightarrow \sf \: \frac{11 \times 2}{2 \times 2} - \frac{5}{4}$

$\longrightarrow \sf \: \frac{22}{4} - \frac{5}{4} = \frac{22 - 5}{4}$

$\longrightarrow \sf \: \frac{17}{4}$

The pineapple is $\sf\frac{17}{4} kg$ more than pear.