Math, asked by kirariff123, 2 months ago

Pinky runs around a rectangular park with the length90m and breadth 45m while Pankaj runs square park of side 75m.Who covers more distance by how much?

Answers

Answered by Sauron
85

Answer:

Pankaj covered 30 m more than Pinky.

Step-by-step explanation:

Pinky runs around a Rectangular park of -

  • Length = 90 m
  • Breadth = 45 m

Pankaj runs around a Square park of -

  • Side = 75 m

To compare the distance covered by them, we need to find perimeter of the respective parks.

Keep in mind that both Pinky and Pankaj ran around the park only once.

Perimeter of Rectangle =

⇒ 2(Length + Breadth)

⇒ 2(90 + 45)

⇒ 2(135)

⇒ 270 m

Perimeter of the rectangular park = 270 m

Pinky covered 270 m.

Perimeter of Square =

⇒ Side × 4

⇒ 75 × 4

⇒ 300 m

Perimeter of the square park = 300 m

Pankaj covered 300 m.

Comparing the distance covered by both =

  • Pankaj = 300 m
  • Pinky = 270 m

⇒ 300 > 270

Distance covered by Pankaj > Distance covered by Pinky

Pankaj covered more distance.

⇒ 300 - 270

⇒ 30 m

Pankaj covered more distance by 30 m.

Therefore, Pankaj covered 30 m more than Pinky.


amansharma264: Great
Sauron: Thank you Aman! ❤️✨
Answered by thatsgahanakashyap
47

Length of a rectangular park= 90m

Breadth of the park= 45m

Therefore, perimeter of the rectangular park= 2×(90m+45m)

= 2× 135 = 270m

Therefore, Pinky runs around a rectangular park of 270m

Side of a square park= 75m

Therefore, Perimeter= 4×s

= 4×75m

= 300m

Therefore, Pankaj runs around a square park of 300m

Therefore, comparing= 300m, 270m

Therefore, 300m is greater than 270m, Pankaj ran a greater distance

By,

300m-270m

=30m

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