Math, asked by narendrasingh233833, 10 months ago

Pinky runs around a square field of side 75 m, Bob runs around a rectangular field with

length 160 m and breadth 105 m. Who covers more distance and by how much?​

Answers

Answered by saivivek16
8

Step-by-step explanation:

Aloha !

 \text { This is Twilight Astro}

perimeter=2 (length + Breadth)

Given,

length 160 m and breadth 105 m

So,

perimeter= 2(160+105)

perimeter=2(265)

perimeter=530m

Pinky already runs around 75m

Then,.

530m-75m

=455 m

Thank you

@ Twilight Astro ✌️☺️

Answered by Cynefin
68

 \huge{ \bold{ \star{ \underline{ \red{ \: Question..}}}}}

✏Pinky runs around a square field of side 75 m, Bob runs around a rectangular field with length 160 m and breadth 105 m. Who covers more distance and by how much?

 \huge{ \bold{ \star{ \underline{ \red{ \: Answer...}}}}}

✒ Bob cover more distance than sneha and by 230m

  \huge{ \bold{ \star{ \underline{ \red{ \: Solution...}}}}}

⚜GIVEN....

✒Pinky runs around a square field.

✒Length of each side of square field= 75m

✒Bob runs around a rectangular field.

✒Length of Rec. field =160 m ,breadth=105m

⚜TO FIND...

✒Who runs more and by how much...?

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 \large{ \sf{ \star{pinky \: runs \: around \: the \: boundary \: of \: square \: field}}} \\  \large{ \sf{ \red{ \longrightarrow{she \: covers \: distance = perimeter \: of \: square}}}} \\  \\  \large{ \sf{we \: know ...\: perimeter \: of \: square}} \\  \large{ \sf{ \boxed{ \star{ \green{perimeter \: of \: square \: field = 4 \times (side)}}}}} \\  \\  \large{ \sf{ \mapsto{ \purple{by \: using \: formula...}}}} \\  \\  :  \large{ \sf{ \implies{side \: of \: square = 75m}}} \\  \\  :  \large{ \sf{ \implies{perimeter \: of \: square = 4 \times 75m}}} \\   \large{ \sf{   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 300m}} \\  \\  \\  \large{ \sf{ \star{bob \: runs \: around \: the \: rectangle \: field}}} \\  \large{ \sf{ \red{ \longrightarrow{he \: covers \: distance = perimeter \: of \: rectangle}}}} \\  \\  \large{ \sf{we \: know...perimeter \: of \: rectangle}} \\  \large{ \star{ \boxed{ \green{perimeter \: of \: rectangle = 2(length + breadth)}}}} \\  \\  \large{ \sf{ \mapsto{ \purple{by \: using \: this \: formula...}}}} \\  \\  :  \large{ \sf{ \implies{length \:  = 160 \: m \:  and  \: breadth = 105m}}} \\  \\  :  \large{ \sf{ \implies{perimeter \: of \: rectangle = 2(160 + 105)m}}} \\   \large{ \sf{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 2(265)m}} \\  \large{ \sf{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 530m}} \\  \\  \\  :  \large{ \sf{ \implies{ \green{530m > 300}}}} \\  \\  :  \large{ \sf{ \implies{perimeter \: of \: rectangle > perimeter \: of \: square}}} \\  \\ :   \large{ \sf{ \implies{ \purple{ \boxed{dis. \: covered \: by \: bob > dis. \: covered \: by \: sneha}}}}}\\  \\    \\ : \large{ \sf{530m - 300m = 230m}} \\  \large{ \sf{ \red{ \longrightarrow{and \: by \:  \boxed{230m} \: more \: distance \: than \: sneha}}}}

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 \large{ \bold{ \purple{ \underline{required \: answer \: is \: bob \: and \: by \: 230 \: m}}}}

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