Question

Pinky spent 3/5 of her money on a handbag and the rest of the money on a dress and a belt. The handbag cost twice as much as the dress. The dress cost rs 20 more than the belt. How much money did she have in the beginning

Answer 1

Let the total money she had be x
So, cost of handbag h = 3/5 x....(1)
Cost of dress d and belt b together = remaining of x = 2/5 x
d + b = 2/5 x....(2)
cost of handbag = 2 cost of dress
h = 2d....(3)
and, cost of dress = cost of belt + 20
d = b + 20....(4)
solving (2) and (4) we get
d + b = 2/5 x
d - b = 20
adding, we get
2d = 2/5 x + 20
Now, we have (3) h = 2d and (1) h = 3/5 x, so 2d = 3/5x
Putting this, we get
3/5 x = 2/5 x + 20
1/5 x = 20
x = 100
Therefore, Riya had Rs 100 in the beginning.

Answer 2

Question :-

Pinky spent 3/5 of her money on a handbag and the rest of the money on a dress and a belt. The handbag cost twice as much as the dress. The dress cost rs 20 more than the belt. How much money did she have in the beginning

Answer :-

Let the total money she had be x

So, cost of handbag h = 3/5 x...(1)

cost of dress d and belt b together = remaining of x = 2/5 x

d + b = 2/5 x....(2)

cost of handbag = 2 cost of dress

h = 2d....(3)

and, cost of dress = cost of belt + 20

d = b + 20.....(4)

solving (2) and (4) we get,

d + b = 2/5 x

d - b = 20

adding we get,

2d = 2/5x + 20

1/5x = 20

x = 100

Therefore Pinky had Rs. 100 in the beginning.

Thanks