Pipe A and B fill a cistern in 2 and 3 hours, but pipe C empties the cistern in 4 hours, then their combine work of 1 hour is
Answers
Answered by
15
pipe A fill a cistern in 2 hours
pipe A fils 1/2 in 1 hours
pipe B fill a cistern in 3 hours
pipe B fills 1/3 in 1 hours
pipe c fills a cistern In 4 hours
pipe c fills 1/4 In 1 hours
their combine work of 1 hour=1/2+1/3+1/4
therefore combine work of 1 hour =6+4+3/12=13/12
they fill 13/12 in 1 hours
they fill full cistern in 1÷13/12
they fill full cistern in 12/13
Similar questions