Math, asked by pandeypriya1033, 2 days ago

Pipe A can fill a cistern in 5 hours and pipe B in 10 hours. Both the pipes are opened together and after 2 hours pipe A is closed, how much time will the pipe B take to fill up the remaining part of a tank?​

Answers

Answered by YennyPenny
0

Step-by-step explanation:

Let "60 units" represent the total water needed for the cistern to fill.

1) Find how many units can pipe A fill for an hour.

  60 units / 5 hours = 12 units

  Pipe A can fill 12 units for 1 hour.

2) Find how many units can pipe B fill for an hour.

   60 units / 10 hours = 6 units

   Pipe B can fill 6 units for 1 hour.

3) Find how many units did Pipe A fill for 2 hours after it closed.

   12 units x 2 hours = 24 units

   Pipe A fills 24 units in 2 hours before it closed.

4) Find how long will it take for pipe B to fill the remaining.

   60 units - 24 units = 36 units

   Pipe B needs to fill 36 units in the cistern to fill it up.

   36 units / 6 units = 6 hours

Answer:

It will take 6 hours for pipe B to fill the remaining part of a tank.

 

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