Question

pipe A can fill a cistern in 5 hours and pipi B can fill it in 6 hours. both the pipes are opened and after two hours , pipe A is closed. how much time will B take to fill the remaining part of the tank.​

Answer 1

Answer:

KAJSGDKEKEKENwjushshw

Answer 2

Answer:

Pipe A can fill an empty tank in 6 hours and pipe B in 8 hours. If both the pipes are opened and after 2 hours pipe A is closed, how much time B will take to fill the remaining tank?

$[A]2\tfrac{1}{3}\ hours$

$[B]3\tfrac{1}{3}\ hours$

$[C]2\tfrac{2}{5}\ hours$

$[D]7\tfrac{1}{2}\ hours$

$3\tfrac{1}{3}\ hours$

Part of the tank filled by pipe A and B in 2 hours

$= 2\left ( \frac{1}{6}+\frac{1}{8} \right )$

$= 2\left ( \frac{4+3}{24} \right ) = \frac{7}{12}$

$\sf \: Remaining \: part = 1-\frac{7}{12} = \frac{5}{12}$

This part is filled by pipe B.

$\sf \: ∴ Required \: Time = \frac{5}{12}\times 8 = \frac{10}{3} = 3\frac{1}{3}\ hours$

Hence option [B] is correct answer.