Question

Pipe a can fill a cistern in 6 hours and pipe b can fill it in 8 hours. Both the pipes are opened and after two hours. Pipe a is closed. How much time will b take to fill the remaining part of the tank

Answer 1

Answer:

3 hours 20 mins

Step-by-step explanation:

Pipe A can fill the cistern in 6 hours

1 hour = 1/6 of the cistern

Pipe B can find the cistern in 8 hours

1 hour = 1/8 of the cistern

If both worked together

1 hour = 1/6 + 1/8 = 7/24 of the cistern

2 hours = 7/24 x 2 = 7/12 of the cistern

Find amount of work left after 2 hours

work left = 1 - 7/12 = 5/12 of the cistern

Find the amount of time needed for B to finish the rest of the work:

1 hour = 1/8 of the cistern

Number of hours needed = 5/12 ÷ 1/8 = 3 1/3 hours

3 1/3 hours =  3 hours 20 mins

Answer: It will take 3 hours 20 mins for Pipe B to fill the remaining of the tank.

Answer 2

Step-by-step explanation:

that is the answer so bye