Question

pipe A can fill a cistern in 6 hours and pipe B can fill the same cistern in 10 hours. Find the time taken to fill the cistern, if both the taps are poened together.

Answer 1

Pipe A fill cistern in 6 hours

Pipe B empty cistern ? hours

both pipe open then cistern filled in 7 hours

lcm of 6 and 7 is 42

one hr work of A is 7 and one hr work of B is 6 hrs

hence pipe B’s one hr work =1

hence pipe B can empty cistern is 42/1=42 hour.

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Answer 2

Answer:

Step-by-step explanation:

One hour work of tapA=1/6

One hour work of tapB=1/10

One hour work of both tap A and tapB=1/6+1/10

=4/15

TIME TAKEN BY BOTH A AND B=15/4 HOURS