Math, asked by ripanripon644, 6 hours ago

pipe a can fill a cistern is 56 minutes while pipe B can empty in 70 minutes both pipes were opened simultaneously at the end of 10 minutes B was closed time take by a to fill the remaining part of the cistern?
1)48 minutes
2) 54 minutes
3) 51 minutes
4) 53 minutes​

Answers

Answered by ujjwalverma1107
0

Answer:

54

Step-by-step explanation:

please mark me as brainlist

Answered by sarojaramanna123
0

Answer:

Total capacity of cistern = LCM of 36 and 48

⇒ Total capacity of cistern = 144 units

Time taken by A to fill cistern = 144/36 = 4

Time taken by B to fill cistern = 144/48 = 3

Pipe B is closed after some time, but pipe A worked for 24 minutes,

In 24 minutes,

Cistern filled by pipe A = 24 × 4 = 96

Remaining units to be filled,

⇒ 144 – 96 = 48

Remaining 48 units was filled by pipe B,

Time taken by pipe B,

⇒ 48/3 = 16 minutes.

∴ Pipe B closed after 16 minutes

Similar questions