Question

Pipe A can fill a tank in 10 h. Pipe B can fill the same tank in
12 h. Pipe C can empty the full tank in 16 h. All the pipes are
opened at 8:00 AM and Pipe A and Bare closed at 10:00 AM.
After how much time from starting will the tank be empty?​

Answer 1

Answer:

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Step-by-step explanation:

5 hours 52 minutes

Answer 2

Answer:

5 hours 52 minutes

Step-by-step explanation:

Let capacity of tank = LCM of (10, 12 and 16) = 240 units

Hence, efficiency of A = 240/10 = 24

Efficiency of B = 240/12 = 20

Efficiency of C = 240/ (-16) = -15 (Outlet pipe)

⇒ All the pipe are opened at 08: 00 am to 10 : 00 am = (24 + 20 – 15) × 2

⇒ All the pipe are opened at 08: 00 am to 10 : 00 am = 29 × 2 = 58

⇒ 58 units will be empty by pipe C = 58/15 hours = 3 hours 52 minutes

⇒ Total time = 2 hours + 3 hours 52 minutes = 5 hours 52 minutes

∴ Total time from starting will the tank be empty in 5 hours 52 minutes.