Pipe A can fill a tank in 12 hours. When it works along with Pipe B, it can fill the tank in 8 hours. In how many hours can pipe B fill the same tank independently?
Answers
Answer:
b=24hours
Step-by-step explanation:
a=12hours
a+b=8hours
1/a+1/b =1/8
1/12+1/b=1/8
1/b=1/8-1/12
1/b=3-2/24
1/b=1/24
b=24hours
Given : Pipe A can fill a tank in 12 hours. When it works along with Pipe B, it can fill the tank in 8 hours
To find: In how many hours can pipe B fill the same tank independently
Solution:
Pipe A can fill a tank in 12 hours.
=> pipe A can fill tank in 1 hr = 1/12
Let say Pipe B can fill Tank in B Hrs
Then Pipe B can fill tank in 1 hrs = 1/B
Pipe A & B together can fill tank in 8 hrs
=> Pipe A & B together can fill in 1 hr = 1/8
1/12 + 1/B = 1/8
multiplying by 24 on both sides
=> 2 + 24/B = 3
=> 24/B = 1
=> B = 24
pipe B fill the same tank independently in 24 hrs
Learn More:
A tank has three pipes. the first pipe can fill 1/2 part of the tank in 1 ...
https://brainly.in/question/1386803
A pipe can fill a water tank in 1 hour .i) What part of the tank is filled ...
https://brainly.in/question/12394488
A pipe can fill the tank in 20 min and another pipe can fill the tank
https://brainly.in/question/9388454