Question

Pipe A can fill a tank in 15 minutes and pipe A and B together can fill the tank in 8 minutes. If pipe B can fill 14 litres per second, then the capacity of tank (in litres) is​

Answer 1

Answer:

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Answer 2

Answer:

Capacity of tank is 14,400 litres

Step-by-step explanation:

Time taken by pipe A alone  = 15 minutes

Time taken by pipe B alone= ?

Time taken by pipes A and B together= 8 minutes

To find time taken by pipe B alone=

$\frac{1}{t_{A+B} } -\frac{1}{t_{A} } =\frac{1}{t_{B} }$

$\\\frac{1}{8} -\frac{1}{15} =\frac{1}{t_{B} }$

$\frac{15-8}{120} =\frac{1}{t_{B} }$

$\frac{7}{120} =\frac{1}{t_{B} }$

$t_{B} = \frac{120}{7} min= \frac{7200}{7} seconds$

as 1 min = 60 seconds

We have got the time taken by pipe B to fill the tank alone and that is 7200/7 seconds

Now,

pipe B can fill in 1 seconds = 14 litres

pipe B can fill in 7200/7 seconds = $\frac{7200}{7}$×14= 14,400 litres