Pipe A can fill a tank in 3 hrs. Pipe B can fill the tank in 4 hrs. Pipe C can empty a full tank in 6 hrs. If all 3 pipes are kept open simultaneously, how long will it take to fill the tank half?
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Answered by
11
Pipe A can fill the tank in = 3 hours
Part of tank filled by A in 1 hour = 1/3
Pipe B can fill the tank in =4 hours
Part of tank filled by B in 1 hour = 1/4
Pipe C can Empty the tank in = 6 hours
Part of tank emptied by C in 1 hour = 1/6
In total, In one Hour
1/3 + 1/4 - 1/6 = 5/12
Therefore the tank can be filled in 12/5 Hours = 2 hours 24 minutes
Part of tank filled by A in 1 hour = 1/3
Pipe B can fill the tank in =4 hours
Part of tank filled by B in 1 hour = 1/4
Pipe C can Empty the tank in = 6 hours
Part of tank emptied by C in 1 hour = 1/6
In total, In one Hour
1/3 + 1/4 - 1/6 = 5/12
Therefore the tank can be filled in 12/5 Hours = 2 hours 24 minutes
Answered by
12
Answer:
1.2 hours
Step-by-step explanation:
A can fill in 1 hr= 1/3
B can fill in 1 hr = 1/4
C can empty in 1 hr = 1/6
together they can fill in 1 hr = 1/3 + 1/4 - 1/6 = 5/12
time taken to full the tank= 1÷5/12= 12/5
time taken to fill the tank half = 12/5 ÷ 2 = 12/5×1/2 = 6/5 = 1.2 hours
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