Pipe A can fill a tank in 5 hours and pipe B can it in 6 hours. If both pipes are opened at the same time, when will the tank be full ?
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I don't know.I don't know.I don't know.I don't know.I don't know.I don't know.I don't know.
MRIDHULMAGESHWARNATH:
What man
Answered by
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Hey......!!! here is ur answer.....☺️☺️☺️
Given that,
Pipe A can fill the tank in 5 hours and pipe B can fill the tank in 6 hours.
Then LCM of 5 and 6 = 30
Then pipe A fill the tank in one hour = 30/5 = 6
and pipe B can fill the tank in 1 hr = 30/6 = 5
Now according to the question......when pipes A and B are opened at the same time
Then, Pipes A and B fill the tank in one hour when they r opened at same time = 6+5 = 11
Then the pipes will be fill the tank in =
total work/time taken in one hour
=> 30/11 hours.
I hope it will help u.......✌️✌️✌️
Given that,
Pipe A can fill the tank in 5 hours and pipe B can fill the tank in 6 hours.
Then LCM of 5 and 6 = 30
Then pipe A fill the tank in one hour = 30/5 = 6
and pipe B can fill the tank in 1 hr = 30/6 = 5
Now according to the question......when pipes A and B are opened at the same time
Then, Pipes A and B fill the tank in one hour when they r opened at same time = 6+5 = 11
Then the pipes will be fill the tank in =
total work/time taken in one hour
=> 30/11 hours.
I hope it will help u.......✌️✌️✌️
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