Pipe a can fill a tank three times faster than pipe b. If together a and b can fill the tank in 40 minutes, then b alone will be able to fill the tank in:
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Let the volume of the tank be y
Let the speed at which pipe b fills be x.
So speed of pipe a will be 3x.
Total speed is 4x.
y/4x = 40
y = 160x
Now b is alone, so the total speed is x.
y/x = z
y = zx
Now equating the RHS of both the equation :
160x = zx
z = 160 mins
Let the speed at which pipe b fills be x.
So speed of pipe a will be 3x.
Total speed is 4x.
y/4x = 40
y = 160x
Now b is alone, so the total speed is x.
y/x = z
y = zx
Now equating the RHS of both the equation :
160x = zx
z = 160 mins
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