Question

Pipe A can fill an empty cistern in 6 hours while along
with Pipe B it can fill it up in 4 hours. Only Pipe B is
on for an hour after which Pipe A is also turned on.
How much time will it take in all to fill up the cistern?​

Answer 1

Answer:

3hours 60 minutes

Step-by-step explanation:

pipe A can fill the cistern in 6hours in

in 1 hour =1/6 of the cistern can be filled.

pipe be can be filled the cistern in 4hours

find the cistern in 1 hour = 1/4 of the cistern be filled.

if they both Will combined together

the work was left =1-5/12=12/12-5 -5/12=7/12

In 1 hour = 16

no. of hours needed = 7/12÷ 1/6= 7/12*6

= 42/12

= 3•5 hours

=3hours

= (0•5*60)

= 3hours (0•5* 60)

= 3hours60 minutes