Question

Pipe A can fill an empty tank in 36 hours. Pipe B can fill the same empty tank in 28 hours. At first pipe A is opened for 4.5 hours and then it is closed. After that pipe B was opened, in how much time pipe B can fill the remaining tank ? (in​

Answer 1

Step-by-step explanation:

Let x be the time taken by B alone to fill remaining tank

Time taken by pipe A is 36 hours

so for 1 hr Pipe A can fill (1/36) part

Time taken by pipe B is 28 hours

so for 1 hr Pipe B can fill (1/28) part

$\frac{1}{36} \times 4.5 + \frac{1}{28} \times x = 1$

$x = \frac{7 \times 28}{8} = 24.5hrs$

so B takes 24.5 hrs more to fill the tank