Math, asked by yashraj790, 10 months ago

pipe A can fill an overhead tank in 10 hrs and pipe B in 15 hrs both the pipe are opened and after 4hrs pipe B is closed.how much time will A can fill the remaining part of the tank​

Answers

Answered by rajputsing88585
0

Step-by-step explanation:

A can fill tank in 10hrs

work done per hour by A= 1/10

B can fill tank in 15hrs

work done by B= 1/15

thus, work done by (A+B) in 1 hour= (1/10+1/15)= 5/30.

work done by both in 4 hours = (5/30x2) = 5/15

Remaining part= (1-5/15) = 10/15

Now, A will be fill it in 10/15hours.

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