Question

pipe a filled a tank in 6 hour.pipe b empty a tank in 8 hours.both pipe start there work.after some time stop the pipe b.so finally tank filled in 13 hour.find the hour of b they open for how many hour.​

Answer 1

Answer:

Part of the tank filled by pipe A and B in 2 hours

= 2\left ( \frac{1}{6}+\frac{1}{8} \right )

= 2\left ( \frac{4+3}{24} \right ) = \frac{7}{12}

Remaining part = 1-\frac{7}{12} = \frac{5}{12}

This part is filled by pipe B.

∴ Required Time = \frac{5}{12}\times 8 = \frac{10}{3} = 3\frac{1}{3}\ hours

Step-by-step explanation:

Hope it helps you

Please mark me as the brainliest