Question

Pipe A tokes 24 minute to fill a tank. Pipe B takes 32 minutes to fill the same
tank. If both the pipes are opened simultaneously, after how much time should
pipe A be closed so that it takes 16 minute to fill the tank.​

Answer 1

Given

• Two pipes can fill a tank in 24 min and 32 min respectively.

To find

• The time after which B should be closed so that the tank is full in 18 min.

Approach and Working out

From the question, it seems one pipe is A and another is B.

So, pipe A will be open for complete 18 mins and Pipe B will be open for some time.

Let, the capacity of the tank = LCM (24, 32) = 96 Units

• So, capacity of pipe A = 96/24 = 4 units per min

• Capacity of pipe B = 96 /32 = 3 units per mint

Pipe A is open for 18 min. So, 18 * 4 = 72 units of tank will get filled.

• Remaining (96-72) =24 units will be filled by pipe B.

Time taken by pipe B to fill 24 units = 24/3 = 8 min.

So, pipe B will be open for 8 mins.

Answer 2

Answer:

The answer is x = 12 min

Step-by-step explanation:

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