Question

pipe k fills a tank in 30 minutes. pipe l can fill the same tank 5 times as fast as pipe k. if both the pipes were kept open when the tank is empty how much time will it take for the tank to overflow?

Answer 1

time taken by pipe k=30 minute
by I=30/5=6 minute
total capacity of tank=lcm of 6,30
=30ltr
capacity of pipe k per minute=30/30=1 ltr /minute
capacity of pipe I =30/6=5 ltr /minute
tank filled by both pipe k&i in one minute=5+1=6 ltr
total time taken for tank to overflow=30/6=5 minute


second method h
simple ,when do pipe ka tym alag alag diya ho aur both ka nikalana ho
to time taken by both=A×B/A+B
IN TBIS QUESTION,
K TYM=30
ITYM=30/5=6 MINUTE(5TIMES FASTER THAN K MEANS 1/5 TH TYM TAKEN THAN K)
BOTH TYM=30×6/30+6
180/36=5 MINUTSE

Answer 2

Solution:

Let the total capacity of tank be 90 liters.
Capacity of tank filled in 1 minute by K = 3 liters.
Capacity of tank filled in 1 minute by L = 15 liters.
Therefore, capacity of the tank filled by both K and L in 1 minute = 18 liters.

Hence, time taken by both the pipes to overflow the tank = 90/18 = 5 minutes.