Pipe X can fill a tank in 10 hours while pipe Y can do the same in 15 hours. How long will they takes
the tank, if both the pipes are opened simultaneously?
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Answers
Answer:
Let the tank be filled up in x hours.
Pipe a can fill a tank in 10 hours
Thus amount filled by pipe a is x/10
Pipe b can empty it in 15 hours
Amount emptied by pipe b is x/15
When the tank become full, means 100% the equation can be debited as :
x/10 - x/15 = 100% or 100/100
(3x - 2x)/30 = 100/100
x /30 = 100/100
100x = 30 ×100
x = 3000/100
x = 30 hours
Thus the tank could be filled up in 30 hours
hope it helps you
Step-by-step explanation:
Pipe a can fill a tank in 10 hours and pipe b can empty it in 15 hours. In how many hours will the tank be filled if both the pipes are opened?
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Let the tank be filled up in x hours.
Pipe a can fill a tank in 10 hours
Thus amount filled by pipe a is x/10
Pipe b can empty it in 15 hours
Amount emptied by pipe b is x/15
When the tank become full, means 100% the equation can be debited as :
x/10 - x/15 = 100% or 100/100
(3x - 2x)/30 = 100/100
x /30 = 100/100
100x = 30 ×100
x = 3000/100
x = 30 hours
Thus the tank could be filled up in 30 hours