Question

Pipe X pours a mixture of acid and water, and pipe Y pours pure water into a bucket. After 1 hour, the bucket got filled and the concentration of acid in the
bucket was noted to be 8%. If pipe Y was closed after 30 minutes and pipe X continued to pour the mixture, concentration of acid in the bucket after 1hour would have been 10%. What is the ratio of acid to the water in the mixture coming out of pipe X?
(A) 13: 2
(B) 2:15
(C) 3:20
(D) 1:5
(E) 2:13​

Answer 1

Step-by-step explanation:

Solve by options

For d

2/(15+10)=8%(satisfy) if both X and Y operates for 1 hr

Flow rate of x=15, y=10

Now we need that value to be 10% if Y operates for half the time than X

X=15(same operates for 1 hr)

Y=5(for 30 min)

2/(15+5)=10% satisfies both the condition

U can try this with other options it won't satisfy both the conditions.