Pipes A and B can fill a tank 30 and 20 hours respectively. Pipe B is opened only for half the time and both pipes are opened for the remaining time. Then tank will be full a) in 15 hours (b) in 20 hours (c) in 25 hours (d) 10 hours
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3
Answer:
a)in 15 hours
Pipe A 1 hr work=1/30
Pipe B 1 hr work=1/20
let total time required to fill the tank =xhrs
since pipe B is open for half hr so work done by pipe B in x/2 hrs =x/40hrs
and work done by pipe (A+B) in remaining x/2 hrs=x/24hrs
so total work done is =x/40+x/24
1=x/40+x/24
=>1=8x/120
=>120=8x
so x=15hrs
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Answered by
1
Answer:
15hours is the answer option a)
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