Pipes A and B can fill a tank in 5 & 6 hrs respectively and pipe C can empty it in 12 hrs . If the tank is half full and all the three pipes are in operation simultaneously then after how much time the tank will be full ? ( Give step by step explanation pls )
Answers
Answered by
1
Answer:
3.5 hours
Step-by-step explanation:
In one hour :
Tank Filled by A = 1/5
Tank Filled by B = 1/6
Tank Empty be C = 1/12
If three pipes are combined then tank filled in one hour =
1/5 + 1/6 - 1/12
= 17/60
17/60 of tanked filled in one hour.
So time taken to fill tank = 60/17 * 1
= 3.5 hours
Answered by
2
Answer:
MARK ME BRAINLIEST........
Attachments:

Similar questions
Math,
3 months ago
Math,
3 months ago
Computer Science,
3 months ago
Math,
6 months ago
Math,
1 year ago