Question

pipes A and B can fill a tank in 5 and 6 hour respectively pipe C empty it in 12 hour the tank is half full all the three pipes are in operation simultaneously after how much time will the tank be full

Answer 1

hello ☺


********I am using LCM method7********

       A --- 5
       B --- 6          
       C --- -12

for total Capacity, take the LCM of 5,6,12 that is 60


Now per hour capacity of A= 60/5 = 12

       per hour capacity of B= 60/6 = 10

       per hour capacity of A= 60/-12 = -5


thus per hour capacity of A+B+C = 12+10-5 = 17

thus total time = total capacity/ per hour capacity = 60/17 hours



thank you