Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. The tank is half full. All the three pipes are in operation simultaneously. After how much time will the tank will be full?
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Answer:
1 13/7 hours.
Step-by-step explanation:
Part of the tank filled in one hour = 5 1 + 6 1 − 12 1 = 12+10−5/60 = 17/60 of the tank is filled
Therefore, 1/2 of the tank is filled in 60/17 × 1/2 = 30/17 hours =1 17 /13 hours.
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