Math, asked by khurshed63, 1 year ago

pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe c can empty it in 12 hours. The tank is half full. All the three pipes are in operation simultaneously. After how much time will the tank will be full?

Answers

Answered by nitin893singh
10
=1/5+1/6-1/12
=11/30-1/12
=(22-5)/60
=17/60
since tank is half full
then all three can fill it in 60/34 hours
Answered by sprao534
7
A, B&C are in operation 1/5+1/6-1/12 =17/60 th part can be filled by three. The time required to complete the remaining part is 30/17 hourd
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