Pipes A and B can fill an empty tank i 40 minutes and 60 minutes, respectively and pipe Calone con empty full tank in x mimes. All the three pipes are opened for 24 minutes and then C closed. A and B together fill the tank in another 16 minutes What is the value of x?
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Let the tank capacity x ltrs.
Water filled by A in one hr is x/10 ltr
Water filled by B is x/ 12 ltr
Water drain by C is x/ 24 ltrs
Now suppose y hrs is required to fill it
Then x.y/10 + x.y/12 — x.y/24 =x
Solving the equation we get 17 y = 120
Y= 120/17 hrs or 7 hrs 3 minutes and 30 Sec approx.
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