Question

Pipes A and B can fill an empty tank in 10 hours and 15 hours respectively. If both are opened together in the empty tank, how much time will they take to fill it complete?​

Answer 1

Answer:

Part filled by A in 1 hr =1/10

Part filled by B in 1 hr =1/15

Part filled by A and B in 1 hr =1/10+1/15

=5/30

=1/6

TIME TAKEN BY AB TO FILL= 1/ 1/6

=6

6hrs. ans

PLEASE MARK AS BRAINLIEST

Answer 2

Given,

• Time taken by Pipe A = 10 hr

• Time taken by Pipe B = 15 hr

$\boxed{\bold{\sf{Time \ Taken \ by \ A \ and \ B =\dfrac{1}{A}+\dfrac{1}{B} }}}$

$\sf{\implies Time \ Taken =\dfrac{1}{10}+\dfrac{1}{15} }$

$\sf{\implies Time \ Taken =\dfrac{15+10}{10\times15}}$

$\sf{\implies Time \ Taken =\dfrac{25}{150}}$

$\sf{\implies Time \ Taken =\dfrac{1}{6}}$

$\boxed{\bold{\sf{Time \ Taken \ by \ AB =\dfrac{1}{\dfrac{1}{A}+\dfrac{1}{B} }}}}$

$\sf{\implies Time \ Taken =\dfrac{1}{\dfrac{1}{6} }}$

$\sf{\implies Time \ Taken =6 \ hours}$

$\huge{\boxed{\bold{\sf{\therefore Time \ Taken =6 \ hours}}}}$