Pipes A and B can fill tank in 5 and 6 hours respectively. Pipe C can empty it in 10 hours.if all the three pipes are opened together, then the tank will be filled in how many hours ?
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Step-by-step explanation:
time taken by a =5
" B = 6
". c= 10
now the total work done by a,b,c = lcm of 5,6,10
= 30
so efficiency of a = 30/5 = 6
" of b = 5
" of c = -3 ( as c empty the tank )
therefore total efficiency = 6+5-3 = 8
so time taken = total work / efficiency
= 30/8
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