Math, asked by harshil5392, 1 year ago

pipes A can fill the tank in 5 hours, pipe B in 10 hours and pipe c in 30 Hours. if all the pipes are open , in how many hours will the tank be filled ​

Answers

Answered by Anonymous
8

a \: can \: fill \: tank \: in \: 1 \: hour =  \frac{1}{5}  \\ b \: can \: fill \: tank \: in \: hour =  \frac{1}{10}  \\ c \: can \: fill \: tank \: in1hour =  \frac{1}{30}  \\  so \: we \: will \: do \: sum \\ (a + b + c) \: in \: 1hr \\  =  \frac{1}{5}  +  \frac{1}{10}  +  \frac{1}{30}  \\  lcm = 30 \\  \frac{6}{30}  +  \frac{3}{30}  +  \frac{1}{30 }  \:   \\   =  \frac{10}{30}  \\  =  \frac{1}{3}

so all pipes can fill tank in 3hour

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