pipes p and q can fill a tank in 12 minutes and 16 minutes respectively. both are kept open for x minutes, and then q is closed. p fills the rest of the tank in 5 minutes. the value of x is:
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Answer:
4 mins
Step-by-step explanation:
Pipe P can fill in 12 mins
⇒ 1 min = 1/12 of the work
Pipe Q can fill in 16 mins
⇒ 1 min = 1/16 of the work
Together, P and Q:
1 min = 1/12 + 1/16 = 7/48
Find the amount of work done P can do in 5 mins:
1 min = 1/12 of the work
5 mins = 1/12 x 5 = 5/12 of the work
Amount of work that was done in x mins:
Amount of work = 1 - 5/12 = 7/12
Find x:
1 min = 7/48 of the work
7/48 of the work = 1 min
1/48 of the work = 1 ÷ 7 = 1/7 min
48/48 of the work = 1/7 x 48 = 48/7 mins
7/12 of the work = 48/7 x 7/12 = 4 mins
Answer: x = 4 mins
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