Question

Pipes x and y can fill a tank in 30 Mins and 60 Mins. both pipes are opened After how much time should x be closed so that the tank is filled in 30 Mins.

Answer 1

Heyya!!!!!!!!!

Here is the answer

pipe y is in operation for 30 mins.

so,

\frac{n}{30} + \frac{30}{60} = 1

n = 15 mins.

Answer 2

The pipe 'x' should be closed after 15 mins  

Given:

x pipe can fill the tank in 30 mins

y pipe can fill the tank in 60 mins

To find:

If both pipes are opened After how much time should x be closed so that the tank is filled in 30 Min

Solution:

The 'x' pipe can fill the tank in 30 mins

The work done by pipe in 1 min = 1/30  

The 'y' pipe can fill the tank in 60 mins  

The work done by pipe in 1 min = 1/60

Let Both pipes opened for ‘z’ mins

The work done in ‘z’ mins = z(1/30 + 1/60)

After ‘z’ min x pipe is closed and ‘y’ completed the work in (30-z) mins

As we know the total work will be 1 unit

=> z(1/30 + 1/60) + (30-z)(1/60) = 1

=> z(2+ 1)/60 + (30 - z)/60 = 1

=> 2z +z + 30 - z = 60

=> 2z = 30

=> z = 15 mins

 

Therefore,

The pipe 'x' should be closed after 15 mins  

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