Question

Pis a point whose ordinate and abscissa are
same. Q = (7, 11). If length of PQ = 20, find the
co-ordinates of P.

Answer 1

Answer:

given Q (7,11) PQ = d=20 units x = y

to find P (x,y)

formula used d = √(x2-x1)^2 + (y2-y1)^2

20 = √ (x-7)^2 + (x-11)^2

20 = √ x^2 + 49 - 14x + x^2 + 121 - 22x

20 = √2x^2 - 36x + 170

squaring both sides,

400 = 2x^2 - 36x + 170

2x^2 - 36x - 230 = 0

x^2 - 18x - 115 = 0

x^2 - 23x + 5x - 115 = 0

x(x - 23) + 5 (x - 23) =0

(x + 5) (x - 23) = 0

x + 5 = 0 and x - 23 = 0

x = -5 and x = 23

coordinates of P (-5,-5) or P(23,23)

Answer 2

Step-by-step explanation:

Here you go hope it helps......