Question

Pis the centre of a circle.
AB diameter A(2,-3) and P(-2,0)
Find co-ordinates of B.​

Answer 1

Answer:

(x, y)= (-6, 3)

Step-by-step explanation:

Centre =p(-2,0)

Diameter has A(2,-3) on one end and B(x, y)on the another

The centre point P divides AB in two equal parts

So, by using midpoint formula,

$-2=\frac{2+x}{2}$

$-4=2+x$

$x=-6$

And,

$0=\frac{-3+y}{2}$

$0=-3+y$

$x=3$

∴(x, y)=(-6, 3)

Answer 2

Centre = P(-2,0)

Diameter has A(2,-3) and B(x,y).

Using the midpoint formula,

$\large\rm { -2 = \frac {2+x}{2}}$

$\large\rm { \implies -4 = 2+x}$

$\large\rm { \therefore x = -6}$

And

$\large\rm { 0 = \frac {-3+y}{2}}$

$\large\rm { \therefore y = 3}$

So, coordinates are (-6,3)