Pis twice as good as Q. Together they finish the work in 14 days. In how many days can Q alone do the same work?
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Answer:
42 is answer hope it help you
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Therefore Q alone completes the same work in 42 days.
Given:
P is twice good as Q. ( P = 2Q )
P and Q together can complete the work in 14 days.
To Find:
The number of days taken by Q to finish the same work =?
Solution:
This numerical can be solved using this simple assumption method.
Let us assume the total work to be finished = 14 × 3 = 42 units
Then the work done by P and Q in one day = 42 / 14 = 3 units
In one day ⇒ P + Q = 3 units
⇒ 2Q + Q = 3 units
⇒ 3Q = 3 units
⇒ Q = 1 units then P = 2Q = 2 × 1 = 2 units
So Q alone can do 1 unit of work in one day
Then to complete the total work of 42 units Q takes 42 / 1 = 42 days
Therefore Q alone completes the same work in 42 days.
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