Question

pitne ka man kis kiska kr rha h??​

Answer 1

Answer:

Given, △ABC∼△PQR, as corresponding sides of similar triangles are proportional,

∴

PQ

AB

=

QR

BC

=

RP

CA

=

k

1

(let)

Also, AB=5,BC=6,AC=7 So, PQ=5k,QR=6k,RP=7k

Perimeter of △PQR=PQ+QR+RP

⇒360=5k+6k+7k⇒360=18k⇒k=20

Thus, PQ=5×20=100,QR=6×20=120,RP=7×20=140